Function Overloading

 

function overloading:

function overloading means using same function name to perform variety of task. But in function overloading we must consider two things. They are:

• 1.       Either the number of arguments in function should be different (the number of input to function should vary).
• 2.       if the number of arguments are same then the data type of the function arguments should be different number of parameter  different.

Note: return type has no role in function overloading

int sum(int a, int b)

{

return (a+b);

}

int sum(int a1, int b1, int c1)

{

return(a1+b1+c1);

}

int sum(int d)

{

return (d+5);

}

void main()

{

cout<<"The sum of one variable"<<sum(10)<<endl;

cout<<"The sum of two variable"<<sum(10,20)<<endl;

cout<<"The sum of three vriable"<<sum(10,20,30)<<endl;

getch();

}

Q. write a program to calculate the area of rectangle and triangle using concept of function overloading.

type II

#include<iostream.h>

#include<conio.h>

using namespace std;

int area(int l, int b)

{

return (l*b)

}

float area(int b, float h)

{

return (0.5*b*h);

}

void main()

{

int l1,b1;

float  h;

cout<<"Enter the value of l1,b1 & h1<<endl;

cin>>l1>>b1>>h1;

cout<<"The area of rectangle is <<area(l1,b1)<<endl;

cout<<"The area of triangle is<<area(l1,h1);

getch();

}